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Guest Stefkov
Posted

I thought I could do thisbut its annoying me. Continuing on from (3)

Hence show that

(big S with 4 at top and 1 at bottom)(x^5/2+1)dx = (65/12)

.....................................................x^2

 

I'm guessing you get rid of the 65/12, that means its equal to so you have to show it equals that.

You have to do the square brackets.

Also I remember being told you have to use the x^(1/2) + x^(-2), from the other part.

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Posted
I thought I could do thisbut its annoying me. Continuing on from (3)

Hence show that

(big S with 4 at top and 1 at bottom)(x^5/2+1)dx = (65/12)

.....................................................x^2

 

I'm guessing you get rid of the 65/12, that means its equal to so you have to show it equals that.

You have to do the square brackets.

Also I remember being told you have to use the x^(1/2) + x^(-2), from the other part.

 

[1->4]S(x^2.5+1)/x^2 dx) = [1->4]S(x^.5+1/x^2 dx) = [1->4][2/3 * x^1.5 - 1/x] = (2/3 * 4^1.5 - 1/4) - (2/3 * 1^1.5 - 1/1) = (16/3 - 1/4) - (2/3 - 1) = (64/12 - 3/12) + 1/3 = 64/12 - 3/12 + 4/12 = 65/12

 

Hope it's readable :bouncy:

 

Edit: here's a more legible version:

Guest Stefkov
Posted

Cheers guys, but just the one more, I've just cant figure out who to do this.

I've got to findthe co-ordinates of A on the picture, you cant see. But

its

3x^2 - 10x + 3

When you gotta find co-ordinates you gotta make

dy=0

dx

so 3x^2 - 10x + 3 = 0

(3x - ?)(x - ?) = 0

And thanks for your help.

Posted
Cheers guys, but just the one more, I've just cant figure out who to do this.

I've got to findthe co-ordinates of A on the picture, you cant see. But

its

3x^2 - 10x + 3

When you gotta find co-ordinates you gotta make

dy=0

dx

so 3x^2 - 10x + 3 = 0

(3x - ?)(x - ?) = 0

And thanks for your help.

 

I don't understand what your asking since nothing will go in those brackets.

Guest Stefkov
Posted

We were told when you have to find a point dy/dx = 0.

So the equation 3x^2 - 10x + 3 = 0.

Now I just have to factorise (that the right word?) it.

I'm pretty sure up to now its (3x - ?)(x - ?)

cos its 3x^2 it has to have 3x in one bracket and x in the other to make the 3x^2. Its just hte numbers that confuse me.

Posted
We were told when you have to find a point dy/dx = 0.

So the equation 3x^2 - 10x + 3 = 0.

Now I just have to factorise (that the right word?) it.

I'm pretty sure up to now its (3x - ?)(x - ?)

cos its 3x^2 it has to have 3x in one bracket and x in the other to make the 3x^2. Its just hte numbers that confuse me.

It's (3x - 1)(x - 3).

Guest Stefkov
Posted

Thanks Supergrunch. Now I will do at least 1 question without any help :heh:

Posted
It's (3x - 1)(x - 3).

 

So he can do, as he says, one question without any help, surely some one should explain how you get that...

 

What you need to do is find two numbers that add to make -10, and also multiply to make 3.

They are -1 and -3 as:

  • 3 (as it's 3x) times -3=-9
  • -9 + -1=-10
  • -3 times -1=3

Guest Stefkov
Posted

I kinda know how to do it, its just remembering how to do it and when theres a 3x like that question it just baffles me sometimes.

Thanks for clearing it up Fish.

Posted
So he can do, as he says, one question without any help, surely some one should explain how you get that...

 

What you need to do is find two numbers that add to make -10, and also multiply to make 3.

They are -1 and -3 as:

  • 3 (as it's 3x) times -3=-9
  • -9 + -1=-10
  • -3 times -1=3

I've already explained how to solve quadratics enough times in this thread...

Posted

The quadratic formula?

 

btw, use www.s-cool.co.uk lots of good stuff there for maths. I used to use it alot for basic trig identities and such.

 

Edit:

 

@blender

depends on notation:

100/3 exactly (best form really, as its exact);

33 and 1/3 (also exact but clumsy);

33.3333 (recurring) (written as 33.3 with a dot over the last 3)(not exact);

or 33.33 (2 decimal points)(not exact);

or 33.333 (5 significant figures)(not exact).

Posted

Curve of x^2, the normal to the curve is at A(1,1), The normal cuts the curve to the left at B.

 

Use differentiation to find the equation of the normal at A. Verify the point where the normal cuts the curve again has coordinates (-3/2 , 9/4).

 

 

I do this by differentiating X^2 ( which is 2x), so the equation of the normal is y= -1/2x ?

 

Then all I need to do is prove (-3/2 , 9/4) satisfies y=-1/2x? (which i don't think it does !_!)

 

 

 

EDIT: Also, how do I find where:

 

y= cuberootX - X^2 crosses the x-axis?

Posted

Differentiating gets you the gradient function, not the equation of the tangent (because the gradient varies along the curve).

 

Substitute (1,1) into the gradient function to find the gradient of the tangent, which is 2. So the gradient of the normal is -1/2. Now we need to find out the value of +c. So we substitute the known co-ordinate into "y=mx+c".

 

1 = -1/2(1) + c

Therefore c = 3/2

 

So equation of normal: y = -1/2x + 3/2

 

To find out the co-ordinates of B, we solve the simultaneous equations (I'll let you do that :heh:)

Posted

i need to know a 'left wing literary critic' by 2moro...someone help!

 

It's VERY important as my coursework needs to be finished within an hour :(

Posted

I REALLY NEED HELP!!

 

I've got a 2500 word essay in tomorrow on why the Tokugawa bakufu collapsed! The problem is the essay isn't supposed to be more than 2500 words!!!

 

ANY tips on how to cut down!! I would really appreciate it!!

Posted

Didn't know whether to post this in the Politics thread, or this one. But I think it is more suited for here. So/

 

Hey, any Scottish people out there, who know a wee thing about politics, do the Scottish Parliamentry elections get much antetnion?

 

It's for an essay I'm doing contrasting General elections with Scottish and European elections, and I know that not much attention is given to European elections, (29% turnout!) but I haven't the foggiest on how big a deal Scottish Parliamentry Elections are.

 

Any help would be greatly appreciated.

Posted
I REALLY NEED HELP!!

 

I've got a 2500 word essay in tomorrow on why the Tokugawa bakufu collapsed! The problem is the essay isn't supposed to be more than 2500 words!!!

 

ANY tips on how to cut down!! I would really appreciate it!!

Write it in Japanese- 1 word per sentence. :heh:

Posted

Who knows about statistical analyses? Namely, mutliple regressions in spss and how to interpret what you get out. I have 3 IVs(extraversion, neuroticism and gender) and 1 DV(luckiness score). They're all continuous, except gender of course, because...welll, because.

Posted

I need some help from you Chemistry wizzes out there, I need examples of Metallic Bonds, Covalent Bonds and Ionic Bonds due to me being useless at the subject and can't figure them out for myself.

 

P.S. The more, the better.


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