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Supergrunch

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Everything posted by Supergrunch

  1. Happy birthday to all! (excluding those whose birthday it isn't)
  2. Yeah, basically each arc is a different way in which things could have happened, starting from (roughly) the same point. And the first arc is episodes 1-4.
  3. I'm trying to pack... so far I have got together a 4 or 5 foot pile of books.
  4. Heheheh, it's barely got going yet. ...you are watching season 1, right?
  5. Unless you believe UK created the universe, I don't think a discussion of him is relevant.
  6. ...if you say so. I should probably point out that people aren't persecuting you as such - just arguing against your opinions. For the time being, anyway (partly as this thread will only cases arguments): [locked]
  7. Well, I had a look at my lecture timetable... I have lectures from 9 to 11 every day apart from Sunday, and then practicals in the afternoons. However, I do have the time to go to the odd intermediate Japanese lecture. Ah well, I'd better start packing for going up on Saturday...
  8. Nope, nothing happens at all. I think it's got to be broken, I'm sending it back.
  9. Use the method I gave, using the 3 equations, then just simplify. To give you something to aim for, you should get: 2P(x^2) - (4A+(P^2))x + 4AP = 0 Then simply substitute in values of A and P and solve. I think only equation 2 has imaginary solutions, and if the question is as you said it is then you don't need to give them. (out of interest, is this FP1?) Edit: A bit more help - although x is greater than 0, that's a red herring - this question is simply straightforward algebra. Using what I said in my previous post, substituting into the third equation we get: x + 2A/x + sqrt((x^2) + ((2A/x)^2)) = P Rearrange this so the sqrt is on one side, then square both sides and simplify to get the quadratic I gave earlier.
  10. Try calling the sides x, y and z, with z being the hypotenuse. We know three things: x^2 + y^2 = z^2, xy/2 = A, and x + y + z = P. Rearranging the second gives y = 2A/x, and we can substitute this into the first to find z. Then substitute for y and z in the third, and simplify. This gives a quartic, I think you should be able to use the fact that x > 0 to get a quadratic. Edit: I've made an error somewhere, I'm only getting imaginary solutions. But the principle should work. Edit 2: Yep, I checked my working and you get a quadratic.
  11. Well, it'll take a fair bit of algebra (which I'm having a go at), but you need to define the other sides of the triangle in terms of x (pythagoras helps here) and thus define A and P in terms of x, and work from there.
  12. My cousin has an IBM Thinkpad that does that, not sure where he got it from. It works really well and has a load of nice features, but probably costs the earth. (as in, around £2000 or so)
  13. The entire tournament was covered in the manga, but they left it out of the anime. However, you'll probably want to watch the new year specials which cover the qualifiers to decide the teams.
  14. I've just bought a 4gb freecom USB stick, because the whole idea of 4gb of flash memory seemed brilliant to me. Anyway, when I tried to plug it into my laptop, I get no response whatsoever, and the same happened when I plugged it into my dad's desktop. Is it broken, or am I doing something wrong? The device comes with no drivers as it's supposed to be recognised automatically... Edit: Sorry, forgot to mention - both computers are PCs running XP pro.
  15. Hmm, I think I got my New Japanese to English Character dictionary in Borders, so you may be in luck.
  16. WinD will sub it, their head claims they will sub anything related to Higurashi. You may have to wait a bit though - the subs are great, but slow. Incidentally, I just saw the RAW. Things are hotting up, and episode 13 will show you why they called the arc minagoroshi-hen... (slaughter chapter)
  17. For anyone following the whole higurashi cancellage thing, episode 12 just aired, so yay!
  18. Heh, good old ribulose-1,5-bisphosphate carboxylase, making Calvin cycles possible. :wink: Anyway, one left!
  19. That is indeed correct! Yep, that's right... sorry for those who'd already answered a question, rules are rules.
  20. Tut tut, naughty internets. Ah well, 3 left, which can probably all be googled.
  21. Correct! It took people long enough, you just had to google "most shoplifted author".
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