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Posted

Ok, so i've got my math sats tomorrow, i feel pretty confident ( got an 8 in practice), but theres just one thing i cant get my head around and these revision books aren't really making it any simpler. Solving equations is a pretty dark area for me and i've jsut wasted 2 a4 pages trying to work out a probably simple sum that i jsut dont get. If anyone can help me, thanks :grin: .

 

 

Its : 6 over x + 3 = 9 over 5 + 2x

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Posted

SATS don't matter. I was in bottom set for English after I got shit SATS and I got an A in my GCSE.

 

It's all application, who the hell thought 14 year olds would enjoy studying Beowulf? Retards.

 

At GCSE you get to study some great stuff, shuv the SATS.

 

Your starting point would be to get each side on an equal plane.

ignore the division part and concentrate on the numbers you have to start with.

Posted

 

It's all application, who the hell thought 14 year olds would enjoy studying Beowulf? Retards.

 

At GCSE you get to study some great stuff, shuv the SATS.

 

with.

 

Beowulf was complete rubbish IMO.

 

These revision books are clogged up with stupid jokes, as if were in junior school...:hmm:

 

Over as in division.

Guest Stefkov
Posted

i am so not god at amths but ill ive it a try

6/x + 3 = 9/5 + 2x

times both sides by x+3 = (x+3) x (5+2x)

5x + 2x squared +15 + 6x

6=9/11x + 2x squared + 15

now im confused. to think im actually in set 2 and going in for higer. HA.

 

also i fucking hate To Kill a Mockingbird. it gets so tiriing after youve discussed Atticus for the 13th time. and Jem for the 8th time and also Scout for the 25th time.

Posted

Sorry I couldn't help you last night SA, I'm not good at solving equations. At least we both still have a couple more days of revision, Science Paper 1 and 2 tomorrow. I'm at a high level 7 in science, so I'm not too worried. English, not so much either, just maths.

Guest Stefkov
Posted

i think it might actually be

6 = 9x + 27

.....-------

.....11x + 2x squared + 15

 

6 x (11x + 2x squared + 15) = 9x + 27

66x + 12x squared + 90 = 9x + 27

66x + 12x squared + 63 = 9x

12x squared + 63 = -57x

12x + 63 = -7.55x

63 = -19.55x

-1.84 = x

 

:wtf: what did i just do? wit you said the nswer in the book was -1, i nearly got it

Posted
i think it might actually be

6 = 9x + 27

.....-------

.....11x + 2x squared + 15

 

6 x (11x + 2x squared + 15) = 9x + 27

66x + 12x squared + 90 = 9x + 27

66x + 12x squared + 63 = 9x

12x squared + 63 = -57x

12x + 63 = -7.55x

63 = -19.55x

-1.84 = x

 

:wtf: what did i just do? wit you said the nswer in the book was -1, i nearly got it

:wtf: no idea...I'm gonna have another stab at it. This is some stupid sats question.

Guest Stefkov
Posted

yeah id actually like to know at the answer is now..

maybe a maths teacher is registered here..... on these forums

or someone good at maths?

Posted

I am not sure what this "over" exactly means but I will give it a try (my maths english is not the best):

 

 

6/x + 3 = 9/5 + 2x

 

1. step get rid of the division stuff by multiplying with 5x

2. put everything on one side so you get something + something = 0

3 use the damn formula

 

Solving quadratic equotations:

 

if the equotation is like: ax^2 + bx + c = 0 then we can use this formula:

 

x(1,2) = (-b +/- sqrt(b^2 - 4ac)) / 2a

 

 

x1 = (sqrt(309) + 3) / 10 and x2 = (sqrt(309) - 3) / 10

 

 

sqrt = square root

Posted
I am not sure what this "over" exactly means but I will give it a try (my maths english is not the best):

 

 

6/x + 3 = 9/5 + 2x

 

1. step get rid of the division stuff by multiplying with 5x

2. put everything on one side so you get something + something = 0

3 use the damn formula

 

Solving quadratic equotations:

 

if the equotation is like: ax^2 + bx + c = 0 then we can use this formula:

 

x(1,2) = (-b +/- sqrt(b^2 - 4ac)) / 2a

 

 

x1 = (sqrt(309) + 3) / 10 and x2 = (sqrt(309) - 3) / 10

 

 

sqrt = square root

Woah taht stuff is way past what we have learnt:heh:

 

By over i mean

6

---

x+3

Posted
Woah taht stuff is way past what we have learnt:heh:

 

By over i mean

6

---

x+3

 

6/(x+3) is the correct way to write it :heh:

 

/ = divide (which is the same as 'over')

Posted

LOL that makes everything DIFFERENT, now please forget the stuff I posted earlier!

 

So your equotation is:

 

6/(x+3) = 9/(5+2x) ......... / * (x+3)*(5+2x)

 

30 + 12 x = 9x + 27 ......... / -9x, -30

 

3x = -3 ........... / : 3

x = -1

 

Et Voila! Wasn't difficult at all. If you need a further explaination ask me.

Posted

lol. I misread the first post at first. I read it as 6/x + 3. That gives unclean answer. But you mean 6/(x+3), in which case, x is -1.

 

I'd first get rid of divisions in any questions of this sort. Take the denominator and cross it over to the other side, so it becomes:

 

6 ( 5+2x ) = 9 ( x+3 )

 

then expand brackets:

 

30 + 12x = 9x + 27

 

which is

 

3x = -3

 

So:

 

x = -1

 

EDIT: I see system_error also fell into the same trap the first time as I did. lol.


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